The range of the function $f(x) = \frac{1}{\sqrt{x-[x]}}$ is

If $f: R \rightarrow R$ is defined as $f(x) = \frac{x^6}{x^6+2020}$,for all $x \in R$,then the range of $f$ is .......

The domain of the function $f(x) = \frac{1}{\sqrt{[x]^2 - [x] - 6}}$,where $[x]$ is the greatest integer function $\leq x$,is:

If $[x]^2-5[x]+6=0$,where $[.]$ denotes the greatest integer function,then

If $A \subseteq Z$ and the function $f: A \rightarrow R$ is defined by $f(x) = \frac{1}{\sqrt{64 - (0.5)^{24 + x - x^2}}}$,then the sum of all absolute values of elements of $A$ is

The domain of the real valued function $f(x) = \sqrt{9 - \sqrt{x^2 - 144}}$ is